Associative arrays (declare -A) in Bash Scripting - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to declare an associative array named 'colors'.

Bash Scripting

declare [1] colors

Drag options to blanks, or click blank then click option'

A-A

B-a

C-r

D-i

Attempts:

3 left

💡 Hint

Common Mistakes

Using lowercase -a which declares an indexed array instead.

Using options unrelated to arrays like -i or -r.

Use declare -A to create an associative array in bash.

2fill in blank

medium

Complete the code to assign the value 'blue' to the key 'sky' in the associative array 'colors'.

Bash Scripting

colors[[1]]=blue

Drag options to blanks, or click blank then click option'

A'sky'

Bsky

C"sky"

Dsky_key

Attempts:

3 left

💡 Hint

Common Mistakes

Not quoting the key which can cause syntax errors.

Using a different key name than intended.

Keys in associative arrays should be quoted strings to avoid errors.

3fill in blank

hard

Fix the error in the code to print the value of the key 'sky' from the associative array 'colors'.

Bash Scripting

echo ${colors[1]

Drag options to blanks, or click blank then click option'

A<sky>

B(sky)

C{sky}

D[sky]

Attempts:

3 left

💡 Hint

Common Mistakes

Using curly braces or parentheses instead of square brackets.

Forgetting to quote the key if it contains spaces.

Use square brackets [] to access associative array elements in bash.

4fill in blank

hard

Fill both blanks to declare an associative array and assign 'red' to key 'apple'.

Bash Scripting

declare [1] fruits; fruits[[2]]=red

Drag options to blanks, or click blank then click option'

A-A

B"apple"

C'apple'

D-a

Attempts:

3 left

💡 Hint

Common Mistakes

Using lowercase -a which declares indexed arrays.

Not quoting the key string.

Use declare -A to declare associative arrays and quote keys when assigning values.

5fill in blank

hard

Fill all three blanks to create an associative array 'person', assign 'John' to 'name', and print it.

Bash Scripting

declare [1] person; person[[2]]=John; echo ${person[3]

Drag options to blanks, or click blank then click option'

A-A

B"name"

C["name"]

D'name'

Attempts:

3 left

💡 Hint

Common Mistakes

Using wrong declaration option.

Not quoting keys consistently.

Using wrong brackets to access array elements.

Declare with -A, assign with quoted key, and access with square brackets including quotes if needed.