Why input makes scripts interactive in Bash Scripting - Test Your Understanding

Practice - 5 Tasks

1fill in blank

easy

Complete the code to read user input into a variable named 'name'.

Bash Scripting

read [1]

Drag options to blanks, or click blank then click option'

Aname

Binput

Cvar

Duser

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'input' as the variable name instead of 'name'.

Forgetting to specify a variable after 'read'.

The read command stores the input into the variable you specify. Here, name is the variable to hold the input.

2fill in blank

medium

Complete the code to prompt the user with 'Enter your age:' before reading input.

Bash Scripting

read -p "Enter your age: " [1]

Drag options to blanks, or click blank then click option'

Aage

Binput

Cuser

Dvar

Attempts:

3 left

💡 Hint

Common Mistakes

Not using the -p option to show a prompt.

Using a variable name unrelated to the data.

The -p option shows a prompt message. The variable age will store the user's input.

3fill in blank

hard

Fix the error in the code to correctly read input into 'color'.

Bash Scripting

read [1]

Drag options to blanks, or click blank then click option'

Aread

B$color

Ccolor

Dinput

Attempts:

3 left

💡 Hint

Common Mistakes

Using $ before the variable name in the read command.

Trying to use 'read' as a variable name.

When reading input, use the variable name without a dollar sign. Using $color tries to read into the value of the variable, which is incorrect.

4fill in blank

hard

Fill both blanks to read input into 'username' and then print a greeting.

Bash Scripting

read [1]
echo "Hello, $[2]!"

Drag options to blanks, or click blank then click option'

Ausername

Buser

Dname

Attempts:

3 left

💡 Hint

Common Mistakes

Using different variable names for reading and printing.

Forgetting the $ sign when printing the variable.

The read command stores input into username. Then echo prints a greeting using the same variable.

5fill in blank

hard

Fill all three blanks to read a number, check if it is greater than 10, and print a message.

Bash Scripting

read [1]
if [ $[2] [3] 10 ]; then
  echo "Number is greater than 10"
fi

Drag options to blanks, or click blank then click option'

Anumber

C-gt

D-lt

Attempts:

3 left

💡 Hint

Common Mistakes

Using different variable names for reading and checking.

Using the wrong comparison operator.

Forgetting the $ sign when referencing the variable.

First, read input into number. Then check if $number is greater than 10 using -gt. If true, print the message.