You want to write a bash script that prints the third argument passed to it, regardless of how many arguments are given. Which snippet correctly uses shift to achieve this?

hard🚀 Application Q8 of 15

Bash Scripting - User Input

You want to write a bash script that prints the third argument passed to it, regardless of how many arguments are given. Which snippet correctly uses shift to achieve this?

Ashift 1 echo "$3"

Bshift 2 echo "$1"

Cshift 3 echo "$1"

Decho "$3"

Step-by-Step Solution

Solution:

Step 1: Understand argument positions
The third argument is originally $3.
Step 2: Use shift to move $3 to $1
Shifting by 2 removes first two arguments, so $3 becomes $1.
Step 3: Print $1 after shift
Printing $1 now outputs the original third argument.
Final Answer:
shift 2 echo "$1" -> Option B
Quick Check:
shift 2 moves third arg to $1 [OK]

Quick Trick: Shift by N-1 to print Nth argument as $1 [OK]

Common Mistakes:

MISTAKES

Shifting too many or too few arguments
Printing $3 without shifting
Confusing argument positions after shift

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More Bash Scripting Quizzes

You want to write a bash script that prints the third argument passed to it, regardless of how many arguments are given. Which snippet correctly uses shift to achieve this?

Step 1: Understand argument positions

Step 2: Use shift to move $3 to $1

Step 3: Print $1 after shift

Final Answer:

Quick Check:

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