[Solved] What is the problem with this bash script snippet?#!/bin/bash shift -2 echo "$1" - Ans: Negative shift values are invalid and cause an error | Bash Scripting

Bash Scripting - User Input

What is the problem with this bash script snippet?

#!/bin/bash
shift -2
echo "$1"

ANegative shift values are invalid and cause an error

BIt will shift arguments twice correctly

CIt will print the last argument

DIt will ignore the shift command

Step-by-Step Solution

Solution:

Step 1: Check shift argument
The shift command does not accept negative numbers.
Step 2: Effect of negative argument
Using shift -2 results in an error: "shift: negative shift count".
Final Answer:
Negative shift values are invalid and cause an error -> Option A
Quick Check:
Shift argument must be non-negative integer [OK]

Quick Trick: Shift argument cannot be negative [OK]

Common Mistakes:

MISTAKES

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