You want to process all command-line arguments one by one in a bash script using shift. Which script snippet correctly does this?

hard🚀 Application Q15 of 15

Bash Scripting - User Input

You want to process all command-line arguments one by one in a bash script using shift. Which script snippet correctly does this?

Afor arg in "$@"; do shift; echo "$arg"; done

Bwhile [ "$#" -gt 0 ]; do echo "$1"; shift; done

Cshift; while [ "$#" -gt 0 ]; do echo "$1"; done

Dwhile [ "$#" -ge 1 ]; do echo "$2"; shift 2; done

Step-by-Step Solution

Solution:

Step 1: Understand argument count and shifting
Use while [ "$#" -gt 0 ] to loop while arguments remain.
Step 2: Print first argument and shift each iteration
Inside loop, print $1 then shift to move to next argument.
Final Answer:
while [ "$#" -gt 0 ]; do echo "$1"; shift; done -> Option B
Quick Check:
Loop with shift processes all args one by one [OK]

Quick Trick: Use while loop with $# and shift to process args one by one [OK]

Common Mistakes:

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