Prompting with read -p in Bash Scripting - Practice Problems & Coding Challenges

Challenge - 5 Problems

💻 Command Output

intermediate

What is the output of this script?

Consider this bash script snippet that prompts the user for input and then echoes it back:

Bash Scripting

read -p "Enter your name: " name
 echo "Hello, $name!"

A It prints nothing because read -p does not work in bash.

B It prints: Enter your name: Hello, followed by the entered name.

C It prints: Hello, followed by the entered name.

D It prints: Hello, $name! literally without replacing $name.

💡 Hint

The read -p option shows a prompt and stores input in a variable.

The read command with -p shows the prompt and waits for user input, storing it in the variable 'name'. Then echo prints Hello, followed by the input.

💻 Command Output

intermediate

What happens if you run this script?

This script uses read -p but tries to read into two variables:

Bash Scripting

read -p "Enter first and last name: " first last
 echo "First: $first"
 echo "Last: $last"

A It stores the entire input in 'first' and leaves 'last' empty.

B It stores the first character in 'first' and the rest in 'last'.

C It causes a syntax error because read -p cannot read into multiple variables.

D It stores the first word in 'first' and the second word in 'last', then prints both.

💡 Hint

read can split input by spaces into multiple variables.

read splits the input by spaces and assigns the first word to 'first' and the second to 'last'.

📝 Syntax

advanced

Which option correctly uses read -p to prompt and store input?

Select the valid bash command that prompts the user and stores input in variable 'age':

A read -p "Enter your age: " age

B read age -p "Enter your age: "

C read "Enter your age: " -p age

D read -prompt "Enter your age: " age

💡 Hint

The -p option must come immediately after read.

Only 'read -p "prompt" variable' is valid syntax. Others cause errors.

🔧 Debug

advanced

Why does this script not show the prompt?

This script tries to prompt the user but the prompt does not appear:

Bash Scripting

read "Enter your city: " city
 echo "City: $city"

A Because read needs the -p option to show a prompt.

B Because the variable name must come before the prompt string.

C Because the prompt string must be in single quotes, not double quotes.

D Because read cannot store input in a variable named 'city'.

💡 Hint

Check the syntax for showing a prompt with read.

Without -p, read waits for input but does not show a prompt.

🚀 Application

expert

How to securely prompt for a password without echoing input?

You want to prompt the user for a password using read -p but hide the input as they type. Which command achieves this?

A

read -p "Enter password: " -s password
 echo "Password length: ${#password}"

B

read -sp "Enter password: " password
 echo "Password length: ${#password}"

C

read -p "Enter password: " password
 stty -echo
 echo "Password length: ${#password}"

D

read -p "Enter password: " password
 echo "Password: $password"

💡 Hint

Use -s option with read to hide input.

The -s option hides input while typing. It must come with -p for prompt.