Default values for input in Bash Scripting - Practice Problems & Coding Challenges

Challenge - 5 Problems

💻 Command Output

intermediate

What is the output of this Bash script using default values?

Consider the following Bash script snippet. What will it print when run without any arguments?

Bash Scripting

name=${1:-"Guest"}
echo "Hello, $name!"

A Hello, Guest!

B Hello, $1!

C Hello, !

D Syntax error

💡 Hint

Look at how the variable 'name' is assigned using ${1:-"Guest"}.

The syntax ${var:-default} means use 'var' if set and not empty; otherwise, use 'default'. Since no argument is passed, $1 is empty, so 'Guest' is used.

💻 Command Output

intermediate

What does this script output when argument is provided?

What will this Bash script print if run with the argument "Alice"?

Bash Scripting

user=${1:-"Unknown"}
echo "User: $user"

A User: Alice

B User: $1

C User: Unknown

D User:

💡 Hint

Check how the default value is used only if the argument is missing.

Since the argument "Alice" is provided, $1 is set, so the variable 'user' takes the value 'Alice'.

📝 Syntax

advanced

Which option correctly assigns a default value to a variable if input is empty?

You want to assign the variable 'color' to the first argument or default to 'blue' if the argument is empty or unset. Which option is correct?

A color=$1 || blue

B color=${1-blue}

C color=${1:=blue}

D color=${1:-blue}

💡 Hint

Remember that :- uses default if variable is unset or empty.

Option D uses ${1:-blue} which means use $1 if set and not empty; otherwise, use 'blue'. Option D uses - which only substitutes if unset, not empty. Option D assigns 'blue' to $1 which is not intended. Option D is invalid syntax.

🔧 Debug

advanced

Why does this script print an empty string instead of the default?

Given this script: ```bash input=$1 value=${input-"default"} echo "$value" ``` When run without arguments, it prints an empty line. Why?

A Because echo is missing quotes

B Because the quotes around default cause a syntax error

C Because input is set but empty, so ${input-"default"} does not use default

D Because input is not exported

💡 Hint

Check what happens when assigning input=$1 with $1 unset, and note the - operator (no colon).

When run without arguments, $1 is unset. However, `input=$1` assigns an empty string to `input`, so `input` is set but null. The `${input-"default"}` (note: `-` without `:`) uses the value of `input` because it only substitutes if unset, not if empty. Thus, empty is printed.

🚀 Application

expert

How many items are in the array after this script runs?

Consider this Bash script: ```bash args=(${@:-"default"}) echo ${#args[@]} ``` What number will it print if run without any arguments?

A 0

B 1

C The number of positional parameters

D Syntax error

💡 Hint

Think about how ${@:-"default"} behaves when no arguments are passed; ${@} expands to null.

When no arguments are passed, ${@} expands to null (empty), so ${@:-"default"} expands to "default". Then `args=("default")`, so `${#args[@]}` is 1.

Practice

1. What does the expression ${name:-Guest} do in a bash script?

easy

A. It throws an error if name is not set.

B. It assigns 'Guest' to name permanently.

C. It deletes the variable name if it is empty.

D. It uses the value of name if set; otherwise, it uses 'Guest' as default.

Solution

1. Step 1: Understand the syntax ${variable:-default}

   This syntax means: use the value of variable if it is set and not empty; otherwise, use default.

2. Step 2: Apply to ${name:-Guest}

   If name is set and not empty, it returns name. If name is unset or empty, it returns 'Guest'.

3. Final Answer:

   It uses the value of name if set; otherwise, it uses 'Guest' as default. -> Option D

4. Quick Check:

   Default value syntax = It uses the value of name if set; otherwise, it uses 'Guest' as default. [OK]

Hint: Use ${var:-default} to provide fallback values [OK]

Common Mistakes:

• Thinking it assigns the default permanently
• Confusing with ${var:=default} which assigns default
• Assuming it throws error if variable unset

2. Which of the following is the correct syntax to read a variable user with a default value 'admin' if input is empty?

easy

A. read user; user=${user:-admin}

B. read user || user=admin

C. read user && user=admin

D. read user ? user=admin

Solution

1. Step 1: Understand how to read input and set default

   The read command takes input into user. To set a default if empty, use user=${user:-admin}.

2. Step 2: Check each option

   read user; user=${user:-admin} correctly reads input then sets default if empty. Options A, C, D use invalid syntax for default assignment.

3. Final Answer:

   read user; user=${user:-admin} -> Option A

4. Quick Check:

   Correct default syntax after read = read user; user=${user:-admin} [OK]

Hint: Use read then assign default with ${var:-default} [OK]

Common Mistakes:

• Using || or && incorrectly for default assignment
• Trying to assign default inside read command
• Using invalid operators like ? for default

3. What is the output of this script if the user presses Enter without typing anything?

read -p "Enter your city: " city
city=${city:-Unknown}
echo "City: $city"

medium

A. City: city

B. City:

C. City: Unknown

D. Error: city not set

Solution

1. Step 1: Analyze read input behavior

   User presses Enter without input, so city is empty string.

2. Step 2: Apply default value substitution

   city=${city:-Unknown} sets city to 'Unknown' because city is empty.

3. Final Answer:

   City: Unknown -> Option C

4. Quick Check:

   Empty input triggers default = City: Unknown [OK]

Hint: Empty input triggers default with ${var:-default} [OK]

Common Mistakes:

• Expecting empty output instead of default
• Confusing ${var:-default} with ${var-default}
• Assuming error occurs on empty input

4. Identify the error in this script snippet:

read name
name=${name=John}
echo "Name: $name"

medium

A. The echo command syntax is wrong

B. The default value syntax is incorrect; should use :- instead of =

C. The variable name is reserved and cannot be used

D. The read command is missing a prompt

Solution

1. Step 1: Check default value syntax

   The script uses ${name=John} which is invalid for default substitution. The correct syntax is ${name:-John}.

2. Step 2: Confirm other parts

   read without prompt is valid, name is a valid variable, and echo syntax is correct.

3. Final Answer:

   The default value syntax is incorrect; should use :- instead of = -> Option B

4. Quick Check:

   Default syntax requires :- not = [OK]

Hint: Use ${var:-default} not ${var=default} for default values [OK]

Common Mistakes:

• Using = instead of :- for default values
• Thinking read needs a prompt
• Confusing variable names with reserved words

5. You want to write a script that asks for a username and a port number. If the user presses Enter without input, the username should default to 'guest' and the port to '8080'. Which script snippet correctly implements this?

hard

A. read -p "Username: " user
user=${user:-guest}
read -p "Port: " port
port=${port:-8080}
echo "User=$user, Port=$port"

B. read -p "Username: " user
user=${user=guest}
read -p "Port: " port
port=${port=8080}
echo "User=$user, Port=$port"

C. read user
if [ -z "$user" ]; then user=guest; fi
read port
if [ -z "$port" ]; then port=8080; fi
echo "User=$user, Port=$port"

D. read user
user=${user:-guest}
read port
port=${port-8080}
echo "User=$user, Port=$port"

Solution

1. Step 1: Check default value syntax for both variables

   read -p "Username: " user user=${user:-guest} read -p "Port: " port port=${port:-8080} echo "User=$user, Port=$port" uses ${var:-default} which correctly sets default if variable is empty or unset.

2. Step 2: Verify prompt usage and output

   read -p "Username: " user user=${user:-guest} read -p "Port: " port port=${port:-8080} echo "User=$user, Port=$port" uses read -p to prompt user, then sets defaults, then echoes both variables correctly.

3. Final Answer:

   read -p "Username: " user user=${user:-guest} read -p "Port: " port port=${port:-8080} echo "User=$user, Port=$port" -> Option A

4. Quick Check:

   Use ${var:-default} with read -p for defaults = read -p "Username: " user user=${user:-guest} read -p "Port: " port port=${port:-8080} echo "User=$user, Port=$port" [OK]

Hint: Use read -p with ${var:-default} for clean input with defaults [OK]

Common Mistakes:

• Using = instead of :- for defaults
• Not prompting user with read -p
• Using ${var-default} which skips empty but not unset