Input validation and sanitization in Agentic AI - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to check if the input is a non-empty string.

Agentic AI

def is_valid_input(user_input):
    return isinstance(user_input, [1]) and len(user_input) > 0

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Astr

Bint

Clist

Ddict

Attempts:

3 left

💡 Hint

Common Mistakes

Using int or list instead of str

Not checking the length of the input

The function checks if the input is a string and not empty. Using str ensures the input is text.

2fill in blank

medium

Complete the code to remove leading and trailing spaces from the input string.

Agentic AI

def sanitize_input(user_input):
    return user_input.[1]()

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Areplace

Bsplit

Cstrip

Dlower

Attempts:

3 left

💡 Hint

Common Mistakes

Using split() which splits the string

Using replace() without specifying what to replace

The strip() method removes spaces from the start and end of a string, cleaning the input.

3fill in blank

hard

Fix the error in the code to safely convert input to an integer.

Agentic AI

def convert_to_int(user_input):
    try:
        return [1](user_input)
    except ValueError:
        return None

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Abool

Bint

Cfloat

Dstr

Attempts:

3 left

💡 Hint

Common Mistakes

Using str() which does not convert to int

Using float() which converts to decimal numbers

The int() function converts a string to an integer. The try-except block handles invalid inputs safely.

4fill in blank

hard

Fill both blanks to create a dictionary of word lengths for words longer than 3 characters.

Agentic AI

words = ['apple', 'cat', 'banana', 'dog']
lengths = {word: [1] for word in words if len(word) [2] 3}

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Alen(word)

B>

C<

Dword

Attempts:

3 left

💡 Hint

Common Mistakes

Using word instead of len(word)

Using < instead of > in the condition

The dictionary comprehension maps each word to its length if the word length is greater than 3.

5fill in blank

hard

Fill all three blanks to filter and transform a dictionary with values greater than 0.

Agentic AI

data = {'a': 1, 'b': -2, 'c': 3}
result = {{ [1]: [2] for k, v in data.items() if v [3] 0 }}

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Ak.upper()

Bv

C>

Dk

Attempts:

3 left

💡 Hint

Common Mistakes

Using k instead of k.upper()

Using < instead of > in the condition

The comprehension creates a new dictionary with keys in uppercase and values unchanged, only for values greater than zero.