Building custom tools in Agentic AI - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to define a simple tool function that returns the square of a number.

Agentic AI

def square_number(num):
    return num [1] num

Drag options to blanks, or click blank then click option'

A+

B*

C-

D/

Attempts:

3 left

💡 Hint

Common Mistakes

Using + instead of * will add the number to itself, not square it.

Using - or / will cause incorrect results or errors.

The function should multiply the number by itself to get the square. Using * performs multiplication.

2fill in blank

medium

Complete the code to create a tool that checks if a string contains the word 'AI'.

Agentic AI

def contains_ai(text):
    return [1] in text

Drag options to blanks, or click blank then click option'

A'ai'

B'aI'

C'AI'

D'Ai'

Attempts:

3 left

💡 Hint

Common Mistakes

Using lowercase 'ai' will not match uppercase 'AI' in the text.

Using mixed case strings will cause the check to fail.

The function checks if the exact string 'AI' is in the text. The correct case is important.

3fill in blank

hard

Fix the error in the tool that returns the first element of a list.

Agentic AI

def first_element(items):
    return items[1]0

Drag options to blanks, or click blank then click option'

A(

B<

C{

D[

Attempts:

3 left

💡 Hint

Common Mistakes

Using parentheses or curly braces causes syntax errors.

Using angle brackets is invalid syntax in Python.

To access the first element of a list, use square brackets [] with index 0.

4fill in blank

hard

Fill both blanks to create a tool that filters even numbers from a list.

Agentic AI

def filter_even(numbers):
    return [num for num in numbers if num [1] 2 [2] 0]

Drag options to blanks, or click blank then click option'

A%

B==

C!=

D//

Attempts:

3 left

💡 Hint

Common Mistakes

Using integer division // instead of modulus.

Using != instead of == will filter odd numbers instead.

The tool uses the modulus operator % to check if the number divided by 2 has a remainder of 0, meaning it is even.

5fill in blank

hard

Fill all three blanks to create a tool that builds a dictionary of word lengths for words longer than 3 characters.

Agentic AI

def word_lengths(words):
    return { [1]: [2] for word in words if len(word) [3] 3 }

Drag options to blanks, or click blank then click option'

Aword

Blen(word)

C>

D<=

Attempts:

3 left

💡 Hint

Common Mistakes

Using <= instead of > will include shorter words.

Swapping key and value will create incorrect dictionary entries.

The dictionary comprehension uses the word as the key and its length as the value, including only words longer than 3 characters.