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What is the time complexity of the optimized recursive DFS approach to check if a binary tree with n nodes is symmetric?

medium🪤 Complexity Trap Q5 of Q15
Tree: Depth-First Search - Symmetric Tree (DFS Approach)
What is the time complexity of the optimized recursive DFS approach to check if a binary tree with n nodes is symmetric?
AO(n log n) due to recursive calls on subtrees
BO(n^2) because each node compares with all others
CO(n) because each node is visited once in mirrored pairs
DO(log n) due to tree height traversal
Step-by-Step Solution
Solution:
  1. Step 1: Analyze traversal

    The algorithm visits each node once, comparing mirrored nodes simultaneously.
  2. Step 2: Confirm no repeated work

    Each node pair is compared once, so total work is proportional to n nodes.
  3. Final Answer:

    Option C -> Option C
  4. Quick Check:

    Linear time traversal of all nodes [OK]
Quick Trick: Each node visited once in mirrored pairs [OK]
Common Mistakes:
MISTAKES
  • Assuming quadratic due to recursion
  • Confusing with balanced tree complexities
Trap Explanation:
PITFALL
  • Candidates often overestimate complexity thinking recursion causes repeated work, but each node is processed once.
Interviewer Note:
CONTEXT
  • Tests understanding of recursion time complexity in tree traversal
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