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Given the following tree, what does the optimized recursive DFS function return?

easy🧾 Code Trace Q3 of Q15
Tree: Depth-First Search - Symmetric Tree (DFS Approach)
Given the following tree, what does the optimized recursive DFS function return? Tree: 1 / \ 2 2 / \ 3 3 Code snippet: ```python root = TreeNode(1, TreeNode(2, TreeNode(3)), TreeNode(2, None, TreeNode(3))) print(isSymmetric(root)) ```
ATrue
BDepends on tree height
CRaises an exception due to NoneType
DFalse
Step-by-Step Solution
Solution:
  1. Step 1: Trace isMirror on root.left and root.right

    Compare nodes with values 2 and 2: equal, continue.
  2. Step 2: Compare left subtree's left (3) with right subtree's right (3) - equal; compare left subtree's right (None) with right subtree's left (None) - equal.

    Both pairs match in value and structure.
  3. Step 3: Check mirrored children of 3 nodes (both leaves) - both None, so symmetric at leaf level.

    All mirrored pairs match, so tree is symmetric.
  4. Final Answer:

    Option A -> Option A
  5. Quick Check:

    Tree is symmetric due to matching structure and values [OK]
Quick Trick: Check mirrored children presence and values [OK]
Common Mistakes:
MISTAKES
  • Assuming same values mean asymmetric
  • Ignoring None node positions
Trap Explanation:
PITFALL
  • Candidates sometimes overlook mirrored None children matching causing incorrect asymmetry assumption.
Interviewer Note:
CONTEXT
  • Tests candidate's ability to trace recursion and handle None nodes
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