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When is approach (1) preferable over (2)?

hard⚖️ Approach Comparison Q8 of Q15
Tree: Depth-First Search - Flatten Binary Tree to Linked List
Consider two approaches to flatten a binary tree: (1) Brute force preorder traversal collecting nodes in a list and rebuilding the linked list, and (2) Optimal reverse preorder traversal with a global pointer. When is approach (1) preferable over (2)?
AWhen minimizing space usage is critical
BWhen the tree is very deep and recursion stack may overflow
CWhen in-place modification is required
DWhen the tree is balanced and small
Step-by-Step Solution
Solution:
  1. Step 1: Compare space usage

    Brute force uses O(n) extra space; optimal uses O(h) recursion stack.
  2. Step 2: Identify when recursion stack overflow is a concern

    Brute force approach avoids recursion stack, so preferable when tree is very deep and recursion stack may overflow.
  3. Step 3: Determine preference

    Approach (1) is preferable when recursion stack overflow risk exists.
  4. Final Answer:

    Option B -> Option B
  5. Quick Check:

    Brute force avoids recursion stack overflow [OK]
Quick Trick: Brute force avoids recursion stack overflow [OK]
Common Mistakes:
MISTAKES
  • Assuming brute force always better
  • Ignoring space trade-offs
Trap Explanation:
PITFALL
  • Candidates confuse space/time trade-offs and in-place constraints.
Interviewer Note:
CONTEXT
  • Tests understanding of trade-offs between approaches and constraints.
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