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What is the worst-case time complexity of the backtracking solution with pruning for finding all combinations of k distinct numbers from 1 to 9 that sum to n?

medium📊 Complexity Theory Q5 of Q15
Subsets & Combinations - Combination Sum III (K Numbers to N)
What is the worst-case time complexity of the backtracking solution with pruning for finding all combinations of k distinct numbers from 1 to 9 that sum to n?
AO(9^k)
BO(C(9, k) * k)
CO(2^9)
DO(k * n)
Step-by-Step Solution
Solution:
  1. Step 1: Understand search space

    We select k numbers from 9 distinct numbers, so combinations count is C(9, k).
  2. Step 2: Analyze complexity

    Each combination requires O(k) time to build and verify sums.
  3. Final Answer:

    Option B -> Option B
  4. Quick Check:

    Combination count times per-combination cost [OK]
Quick Trick: Complexity depends on combinations count C(9,k) times k [OK]
Common Mistakes:
MISTAKES
  • Assuming exponential 9^k without pruning
  • Confusing with 2^9 subsets instead of k-sized combinations
  • Ignoring per-combination construction cost
Trap Explanation:
PITFALL
  • 9^k looks like brute force but pruning limits to combinations C(9,k).
Interviewer Note:
CONTEXT
  • Tests understanding of combinatorial complexity and pruning impact.
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