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What is the worst-case time complexity of the optimal backtracking solution with sum bound pruning for Combination Sum III (k numbers from 1 to 9 summing to n)?

medium🪤 Complexity Trap Q13 of Q15
Subsets & Combinations - Combination Sum III (K Numbers to N)
What is the worst-case time complexity of the optimal backtracking solution with sum bound pruning for Combination Sum III (k numbers from 1 to 9 summing to n)?
AO(k!) because permutations of k numbers are explored
BO(k * n) because we explore all sums up to n for k elements
CO(n^k) because we try all sequences of length k with sum n
DO(2^9) because each number 1-9 can be either included or excluded, pruning reduces calls but worst case remains exponential
Step-by-Step Solution
  1. Step 1: Identify search space size

    Numbers 1 to 9 can be included or excluded, so 2^9 subsets possible.
  2. Step 2: Consider pruning effect

    Pruning reduces calls but worst-case complexity remains O(2^9) since all subsets might be explored.
  3. Final Answer:

    Option D -> Option D
  4. Quick Check:

    Backtracking worst case is exponential in number of candidates [OK]
Quick Trick: Backtracking subsets of 9 elements is O(2^9) worst case [OK]
Common Mistakes:
MISTAKES
  • Confusing with DP complexity O(k*n)
  • Thinking permutations cause factorial complexity
Trap Explanation:
PITFALL
  • O(k*n) looks plausible but pruning doesn't reduce exponential worst case; permutations are not generated.
Interviewer Note:
CONTEXT
  • Tests if candidate understands exponential nature of backtracking despite pruning.
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