Operating Systems - Paging vs Segmentation - Address Translation
Which of the following statements about segmentation is INCORRECT?
Which of the following statements about segmentation is INCORRECT?
medium🐞 Bug Identification Q14 of Q15
Step-by-Step Solution
Step 1: Analyze Segments can vary in size and represent logical units of a program
Segments are variable-sized logical units; this is correct.Step 2: Analyze Segmentation completely eliminates fragmentation issues
Segmentation does not eliminate fragmentation; it can cause external fragmentation.Step 3: Analyze Segment tables store base and limit for each segment
Segment tables store base and limit addresses; this is correct.Step 4: Analyze Segmentation allows sharing of segments between processes
Segmentation supports sharing segments like code segments; this is correct.Final Answer:
Option A -> Option AQuick Check:
Fragmentation remains a problem in segmentation due to variable sizes.
Quick Trick: Segmentation = variable size -> external fragmentation possible
Common Mistakes:
MISTAKES- Believing segmentation removes all fragmentation
- Confusing segment tables with page tables
- Assuming segments cannot be shared
Trap Explanation:
PITFALL- Option A is incorrect; candidates often mistakenly believe segmentation removes all fragmentation.
Interviewer Note:
CONTEXT- Checks candidate's ability to identify subtle misconceptions about segmentation.
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