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In a Snake and Ladder game design, what is the time complexity of checking and updating a player's position after a dice roll if snakes and ladders are stored in a hash map keyed by start position?

medium🪤 Complexity Trap Q5 of Q15
OOP & Design Patterns - Design Snake and Ladder Game - LLD End-to-End
In a Snake and Ladder game design, what is the time complexity of checking and updating a player's position after a dice roll if snakes and ladders are stored in a hash map keyed by start position?
AO(log n) if snakes and ladders are stored in a balanced tree
BO(1) average time due to direct hash map lookup
CO(n) where n is the number of snakes and ladders, due to iteration
DO(n^2) because each move triggers multiple lookups
Step-by-Step Solution
Solution:
  1. Step 1: Identify data structure

    Snakes and ladders stored in hash map keyed by start position.
  2. Step 2: Lookup operation

    Checking if current position has snake/ladder is a direct hash map lookup -> O(1) average.
  3. Step 3: Update position

    Updating player position is O(1).
  4. Final Answer:

    Option B -> Option B
  5. Quick Check:

    Hash map lookup is constant time on average [OK]
Quick Trick: Hash map lookup -> O(1) average [OK]
Common Mistakes:
MISTAKES
  • Assuming iteration over all snakes/ladders
  • Confusing balanced tree lookup with hash map
  • Overestimating complexity due to multiple moves
Trap Explanation:
PITFALL
  • Candidates often think checking all snakes/ladders requires iteration, missing direct hash map access advantage.
Interviewer Note:
CONTEXT
  • Tests understanding of data structure impact on operation complexity
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