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Two approaches solve Partition Labels: (1) Using a dictionary for last occurrences, (2) Using a fixed-size array for last occurrences. When is approach (1) preferable over (2)?

hard⚖️ Approach Comparison Q8 of Q15
Greedy Algorithms - Partition Labels
Two approaches solve Partition Labels: (1) Using a dictionary for last occurrences, (2) Using a fixed-size array for last occurrences. When is approach (1) preferable over (2)?
AWhen the input string contains only lowercase letters a-z
BWhen the input string is very large and performance is critical
CWhen the character set is large or unknown, e.g., Unicode
DWhen memory usage must be minimized regardless of input
Step-by-Step Solution
Solution:
  1. Step 1: Compare data structures

    Fixed-size array is efficient for small fixed alphabets (a-z), but limited to known size.
  2. Step 2: Identify scenario for dictionary

    Dictionary handles large or unknown character sets (Unicode), adapting dynamically.
  3. Final Answer:

    Option C -> Option C
  4. Quick Check:

    Dictionary preferred for large/unknown alphabets [OK]
Quick Trick: Use dict for large/unknown alphabets [OK]
Common Mistakes:
MISTAKES
  • Assuming array always better
  • Ignoring character set size
  • Confusing memory and speed trade-offs
Trap Explanation:
PITFALL
  • Candidates often overlook character set size and assume fixed array is always best.
Interviewer Note:
CONTEXT
  • Tests trade-off reasoning between data structures.
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