Greedy Algorithms - Minimum Domino Rotations
What is the time complexity of the optimal single-pass greedy solution for the Minimum Domino Rotations problem, given arrays of length n?
What is the time complexity of the optimal single-pass greedy solution for the Minimum Domino Rotations problem, given arrays of length n?
medium🪤 Complexity Trap Q13 of Q15
Step-by-Step Solution
Step 1: Identify loops in the code
The code checks at most two candidates (A[0] and B[0]) and iterates once over all n dominoes per candidate.Step 2: Calculate total operations
Each candidate check is O(n), so total is O(2 * n) = O(n).Final Answer:
Option C -> Option CQuick Check:
Only two passes over n elements -> linear time [OK]
Quick Trick: Only two candidates checked, linear scan each [OK]
Common Mistakes:
MISTAKES- Assuming all 6 numbers checked -> O(6n)
- Confusing nested loops causing O(n^2)
Trap Explanation:
PITFALL- Many think all six numbers are checked, inflating complexity to O(6n).
Interviewer Note:
CONTEXT- Tests understanding of pruning and complexity analysis in greedy solutions.
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