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What is the time complexity of the top-down memoization approach for the Jump Game problem in the worst case, and why is the common belief that it is O(n) incorrect?

medium🪤 Complexity Trap Q5 of Q15
Greedy Algorithms - Jump Game (Can Reach End?)
What is the time complexity of the top-down memoization approach for the Jump Game problem in the worst case, and why is the common belief that it is O(n) incorrect?
AO(n) because each position is visited once
BO(n^2) because each position may recursively explore up to n next positions
CO(2^n) due to exponential recursion without memoization
DO(n log n) due to binary search optimization
Step-by-Step Solution
Solution:
  1. Step 1: Analyze recursion calls

    Each position calls recursive checks for all reachable next positions, up to n in worst case.
  2. Step 2: Memoization reduces repeated calls but nested loops remain

    Memoization avoids repeated work but nested for-loop over reachable positions causes O(n^2) complexity.
  3. Final Answer:

    Option B -> Option B
  4. Quick Check:

    Nested recursion with memo -> O(n^2), not O(n) [OK]
Quick Trick: Nested recursion loops cause O(n^2) time [OK]
Common Mistakes:
MISTAKES
  • Assuming memoization makes it O(n)
  • Ignoring nested loop over reachable positions
Trap Explanation:
PITFALL
  • Candidates think memoization means linear time, but nested loops cause quadratic time.
Interviewer Note:
CONTEXT
  • Tests understanding of recursion + memoization complexity traps.
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