Dynamic Programming: Knapsack - Number of Ways to Make ChangeWhat is the output of the space-optimized code when coins = [3] and amount = 0?A3B1C0DError or exceptionCheck Answer
Step-by-Step SolutionSolution:Step 1: Initialize dp arraydp = [1] since amount=0, dp[0]=1 means one way to make amount 0 (empty set).Step 2: Loop over coins and amountsSince amount=0, inner loop does not run. dp remains [1].Final Answer:Option B -> Option BQuick Check:One way to make amount 0: use no coins -> dp[0]=1 [OK]Quick Trick: Amount zero always has 1 way (empty set) [OK]Common Mistakes:MISTAKESReturning 0 for amount=0Looping incorrectly over dp arrayMisunderstanding base caseTrap Explanation:PITFALLCandidates often forget dp[0]=1 base case, leading to zero count for amount=0.Interviewer Note:CONTEXTTests handling of edge cases and base conditions in DP.
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