Dynamic Programming: Knapsack - Minimum Cost for TicketsWhat is the output of mincostTickets([10], [5,10,20]) using the bottom-up DP code below?A0B10C20D5Check Answer
Step-by-Step SolutionSolution:Step 1: Calculate dp for single travel dayOnly one day (10), dp[1] = 0 (base case), dp[0] = min(5+dp[1],10+dp[1],20+dp[1]) = 5Step 2: Verify output matches cheapest ticketSince dp[0] = 5, output is 5, which corresponds to 5.Final Answer:Option D -> Option DQuick Check:Single day, cheapest ticket cost is 5 [OK]Quick Trick: Single day -> cheapest ticket cost [OK]Common Mistakes:MISTAKESConfusing dp indicesMisreading costs arrayTrap Explanation:PITFALLCandidates sometimes pick cost of longer tickets ignoring cheapest 1-day pass.Interviewer Note:CONTEXTTests code trace on minimal edge case input
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