Dynamic Programming: Knapsack - Integer BreakConsider the same bottom-up DP code for integer break. What is the value of dp[1] and dp[0] after execution?Adp[0] = 1, dp[1] = 1Bdp[0] = 0, dp[1] = 0Cdp[0] = 1, dp[1] = 0Ddp[0] = 0, dp[1] = 1Check Answer
Step-by-Step SolutionSolution:Step 1: Check initializationdp array initialized with zeros; dp[1] explicitly set to 1.Step 2: Loop behavior for n=1Loop from i=2 to n does not run; dp[0] remains 0, dp[1] is 1.Final Answer:Option D -> Option DQuick Check:dp[0]=0, dp[1]=1 as per code [OK]Quick Trick: dp[1] initialized to 1, dp[0] remains zero [OK]Common Mistakes:MISTAKESAssuming dp[0] initialized to 1Ignoring dp[1] initializationTrap Explanation:PITFALLCandidates confuse dp[0] and dp[1] initialization leading to wrong base case understanding.Interviewer Note:CONTEXTTests understanding of base cases and boundary conditions in DP
Master "Integer Break" in Dynamic Programming: Knapsack3 interactive learning modes - each teaches the same concept differentlyTry ItSolutionTrace
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