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Consider the same bottom-up DP code for integer break. What is the value of dp[1] and dp[0] after execution?

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Dynamic Programming: Knapsack - Integer Break
Consider the same bottom-up DP code for integer break. What is the value of dp[1] and dp[0] after execution?
Adp[0] = 1, dp[1] = 1
Bdp[0] = 0, dp[1] = 0
Cdp[0] = 1, dp[1] = 0
Ddp[0] = 0, dp[1] = 1
Step-by-Step Solution
Solution:
  1. Step 1: Check initialization

    dp array initialized with zeros; dp[1] explicitly set to 1.
  2. Step 2: Loop behavior for n=1

    Loop from i=2 to n does not run; dp[0] remains 0, dp[1] is 1.
  3. Final Answer:

    Option D -> Option D
  4. Quick Check:

    dp[0]=0, dp[1]=1 as per code [OK]
Quick Trick: dp[1] initialized to 1, dp[0] remains zero [OK]
Common Mistakes:
MISTAKES
  • Assuming dp[0] initialized to 1
  • Ignoring dp[1] initialization
Trap Explanation:
PITFALL
  • Candidates confuse dp[0] and dp[1] initialization leading to wrong base case understanding.
Interviewer Note:
CONTEXT
  • Tests understanding of base cases and boundary conditions in DP
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