[Solved] What is the output of the following Python function call generate_gray_code(1) given this implementation?def generate_gray_code(n): if n == 0:... | Bit Manipulation

Bit Manipulation - Gray Code

What is the output of the following Python function call generate_gray_code(1) given this implementation?

def generate_gray_code(n):
     if n == 0:
         return [0]
     prev = generate_gray_code(n - 1)
     return prev + [x + (1 << (n - 1)) for x in reversed(prev)]

A[0, 1]

B[0, 1, 3, 2]

C[0, 1, 2, 3]

D[1, 0]

Step-by-Step Solution

Solution:

Step 1: Base case for n=0
The function returns [0].
Step 2: For n=1
prev = generate_gray_code(0) = [0]. Then return prev + [x + (1 << 0) for x in reversed(prev)] = [0] + [0 + 1] = [0, 1].
Final Answer:
Option A -> Option A
Quick Check:
Sequence length is 2^1=2 and consecutive numbers differ by one bit. [OK]

Quick Trick: For n=1, Gray code is always [0,1] [OK]

Common Mistakes:

MISTAKES

Confusing the order of concatenation
Assuming the sequence length is 4 for n=1
Misinterpreting the bit shift operation

Trap Explanation:

PITFALL

Option B looks like Gray code for n=2 but question asks for n=1 output.

Interviewer Note:

CONTEXT

Tests understanding of recursive Gray code generation base and first step.

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More Bit Manipulation Quizzes

What is the output of the following Python function call generate_gray_code(1) given this implementation?

Step 1: Base case for n=0

Step 2: For n=1

Final Answer:

Quick Check:

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