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How does this constraint affect the standard Gray code generation approach?

hard🎤 Interviewer Follow-up Q10 of Q15
Bit Manipulation - Gray Code
Suppose you want to generate a Gray code sequence for n bits but with the constraint that the sequence must start and end with 0. How does this constraint affect the standard Gray code generation approach?
ANo change needed; standard Gray code always starts and ends with 0
BModify the recursive reflected Gray code to exclude last element
CStandard Gray code ends with 2ⁿ-1, so a new approach is required
DUse brute force backtracking to enforce start/end constraints
Step-by-Step Solution
Solution:
  1. Step 1: Analyze standard Gray code start/end

    Standard Gray code starts with 0 but ends with 2ⁿ-1 (not 0).
  2. Step 2: Understand constraint impact

    To start and end with 0, the sequence must be cyclic with one-bit difference between last and first elements, which standard Gray code does not guarantee.
  3. Step 3: Conclusion

    A new approach or modification is required to satisfy this constraint.
  4. Final Answer:

    Option C -> Option C
  5. Quick Check:

    Standard Gray code ends with 2ⁿ-1, so constraint breaks standard approach [OK]
Quick Trick: Standard Gray code ends with 2ⁿ-1, not 0 [OK]
Common Mistakes:
MISTAKES
  • Assuming Gray code is cyclic by default
  • Trying to fix with simple list slicing
Trap Explanation:
PITFALL
  • Candidates often overlook that Gray code is not cyclic and ends with max number.
Interviewer Note:
CONTEXT
  • Tests ability to adapt or rethink standard algorithms under new constraints.
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