Reasoning Ability - Calendar ProblemsWhich year will have the same calendar as 1999?A2005B2004C2006D2010Check Answer
Step-by-Step SolutionStep 1: Identify 1999 type1999 is a non-leap year.Step 2: Try 11-year candidate (1999 → 2010)Leap years between 2000–2009: 2000, 2004, 2008 → 3 leaps; ordinary = 8.Step 3: Compute odd daysOdd days = (8 × 1) + (3 × 2) = 8 + 6 = 14 → 14 ≡ 0 (mod 7) → calendars repeat in 2010.Final Answer:2010 → Option DQuick Check:1999 → 2010 odd days 14 → repeat ✅Quick Trick: Near century boundaries, 11-year repeats are common for ordinary years with appropriate leap counts.Common Mistakes:MISTAKESMiscounting leaps around 2000 boundary.
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