Reasoning Ability - Calendar Problems
The calendar of the year 2010 will repeat again in which of the following years?
The calendar of the year 2010 will repeat again in which of the following years?
easy Q11 of 15
Step-by-Step Solution
Step 1: Identify 2010 type
2010 is a non-leap year → contributes 1 odd day per ordinary year.Step 2: Consider candidate 2021 (11 years later)
Count leap years between 2010–2020: 2012, 2016, 2020 = 3 leap years; ordinary years = 8.Step 3: Compute odd days
Odd days = (8 × 1) + (3 × 2) = 8 + 6 = 14 → 14 mod 7 = 0.Final Answer:
2021 → Option AQuick Check:
Total odd days ≡ 0 (mod 7) → calendars match ✅
Quick Trick: Sum ordinary years as +1 and leap years as +2; if total ≡ 0 (mod 7), calendars repeat.
Common Mistakes:
MISTAKES- Assuming fixed 6-year repeat without checking intervening leap years.
Master "Calendar Problems" in Reasoning Ability
Start learning the concept with an interactive lesson.
Want More Practice?
15+ quiz questions · All difficulty levels · Free
Free Signup - Practice All QuestionsMore Reasoning Ability Quizzes