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SSC CGL 2024: A machine does 2000 Joules of work in 4 seconds. If the efficiency of the machine is 50%, what is the power input to the machine?

hard Q9 of 15
General Science - Physics (Basics)
SSC CGL 2024: A machine does 2000 Joules of work in 4 seconds. If the efficiency of the machine is 50%, what is the power input to the machine?
A4000 Watts
B500 Watts
C2000 Watts
D1000 Watts
Step-by-Step Solution
  1. Step 1: Understand power and efficiency

    Power output = Work done / Time; Efficiency = (Power output / Power input) × 100%.
  2. Step 2: Calculate power output

    Work done = 2000 Joules, Time = 4 seconds.
    Power output = 2000 / 4 = 500 Watts.
  3. Step 3: Calculate power input

    Efficiency = 50% = (Power output / Power input) × 100.
    Power input = Power output / (Efficiency / 100) = 500 / 0.5 = 1000 Watts.
  4. Step 4: Recheck options

    1000 Watts is 1000 Watts, but check carefully.
  5. Step 5: Correction

    Recalculate: Power output = 2000 / 4 = 500 Watts.
    Power input = 500 / 0.5 = 1000 Watts.
  6. Final Answer:

    1000 Watts → Option D
  7. Quick Check:

    Power input = Power output / Efficiency fraction = 1000 Watts ✅
Quick Trick: Power input = Power output ÷ (Efficiency/100).
Common Mistakes:
MISTAKES
  • Confusing power input with output or ignoring efficiency.
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