[Solved] Which Python code snippet correctly creates a Flask route to handle GET requests at '/status'? - Ans: @app.route('/status', methods=['GET']) def status(): return 'OK' | Raspberry Pi

Raspberry Pi - Web Server and API

Which Python code snippet correctly creates a Flask route to handle GET requests at '/status'?

A@app.route('/status', methods=['PUT']) def status(): return 'OK'

B@app.route('/status', methods=['GET']) def status(): return 'OK'

C@app.route('/status', methods=['POST']) def status(): return 'OK'

D@app.route('/status'methods=['GET']) def status(): return 'OK'

Step-by-Step Solution

Solution:

Step 1: Identify correct HTTP method for GET
GET requests require methods=['GET'] in route decorator.
Step 2: Check route syntax
@app.route('/status', methods=['GET']) is correct syntax for GET route.
Final Answer:
Decorator with methods=['GET'] and function returning 'OK' -> Option B
Quick Check:
Flask GET route syntax = @app.route('/status', methods=['GET']) def status(): return 'OK' [OK]

Quick Trick: Use methods=['GET'] to specify GET routes in Flask [OK]

Common Mistakes:

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Which Python code snippet correctly creates a Flask route to handle GET requests at '/status'?