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You want to read all 8 channels of the MCP3008 and store their values in a dictionary with keys as channel numbers. Which code snippet correctly implements this using spidev?

hard🚀 Application Q15 of 15
Raspberry Pi - SPI Communication
You want to read all 8 channels of the MCP3008 and store their values in a dictionary with keys as channel numbers. Which code snippet correctly implements this using spidev?
Avalues = {ch: ((spi.xfer2([1, (8 + ch) << 4, 0])[1] & 3) << 8) + spi.xfer2([1, (8 + ch) << 4, 0])[2] for ch in range(8)}
Bvalues = {} for ch in range(8): adc = spi.xfer2([1, (8 + ch) << 4, 0]) values[ch] = ((adc[1] & 3) << 8) + adc[2]
Cvalues = [spi.xfer2([1, (8 + ch) << 4, 0]) for ch in range(8)]
Dvalues = {ch: spi.xfer2([1, (8 + ch) << 4, 0])[1] << 8 + spi.xfer2([1, (8 + ch) << 4, 0])[2] for ch in range(8)}
Step-by-Step Solution
Solution:
  1. Step 1: Understand correct SPI read and bit extraction

    Each channel read requires one SPI transfer. The 10-bit value is extracted by masking adc[1] with 3 and shifting before adding adc[2].
  2. Step 2: Check code correctness

    values = {} for ch in range(8): adc = spi.xfer2([1, (8 + ch) << 4, 0]) values[ch] = ((adc[1] & 3) << 8) + adc[2] uses a for loop to read each channel once, extracts the value correctly, and stores it in a dictionary with channel keys.
  3. Final Answer:

    Option B code snippet -> Option B
  4. Quick Check:

    Loop + mask adc[1] & 3 + shift + store in dict [OK]
Quick Trick: Use a loop with masking and shifting to read all channels [OK]
Common Mistakes:
MISTAKES
  • Calling spi.xfer2 twice per channel (Option A)
  • Not masking adc[1] bits (Option D)
  • Storing raw SPI response without processing (Option C)

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