[Solved] What will be the output of this Python code controlling LEDs on Raspberry Pi?import RPi.GPIO as GPIO import time GPIO.setmode(GPIO.BCM) GPIO.setup([17, 18], GPIO.OUT) for pin in [17, 18]: GPIO.... | Raspberry Pi

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What will be the output of this Python code controlling LEDs on Raspberry Pi?

import RPi.GPIO as GPIO
import time

GPIO.setmode(GPIO.BCM)
GPIO.setup([17, 18], GPIO.OUT)

for pin in [17, 18]:
    GPIO.output(pin, GPIO.HIGH)
    time.sleep(0.5)
    GPIO.output(pin, GPIO.LOW)

GPIO.cleanup()

ALED on pin 17 turns on for 0.5s, then off; then LED on pin 18 turns on for 0.5s, then off

BBoth LEDs turn on and off together for 0.5s

COnly LED on pin 18 blinks twice

DSyntax error due to GPIO.output usage

Step-by-Step Solution

Solution:

Step 1: Analyze the for loop behavior
The loop turns on pin 17 LED, waits 0.5 seconds, then turns it off, then repeats for pin 18.
Step 2: Understand timing and output
LEDs blink one after another, not together, each for 0.5 seconds.
Final Answer:
LED on pin 17 turns on for 0.5s, then off; then LED on pin 18 turns on for 0.5s, then off -> Option A
Quick Check:
Sequential LED blinking = LED on pin 17 turns on for 0.5s, then off; then LED on pin 18 turns on for 0.5s, then off [OK]

Quick Trick: Check loop order and sleep timing carefully [OK]

Common Mistakes:

Assuming LEDs blink simultaneously
Confusing pin numbers
Thinking code has syntax errors

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What will be the output of this Python code controlling LEDs on Raspberry Pi?

Step 1: Analyze the for loop behavior

Step 2: Understand timing and output

Final Answer:

Quick Check:

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