[Solved] Consider this code snippet for an EV's security system:def check_access(password): if password == 'Secure123': return 'Access granted' else:... | EV Technology

EV Technology - Connected Vehicle (V2X)

Consider this code snippet for an EV's security system:

def check_access(password):
    if password == 'Secure123':
        return 'Access granted'
    else:
        return 'Access denied'

print(check_access('secure123'))

What will be the output?

AAccess granted

BSyntaxError

CNone

DAccess denied

Step-by-Step Solution

Solution:

Step 1: Understand the password check logic
The function compares the input password exactly to 'Secure123' with case sensitivity.
Step 2: Check the input password 'secure123'
The input 'secure123' differs in case from 'Secure123', so the condition fails and returns 'Access denied'.
Final Answer:
Access denied -> Option D
Quick Check:
Case mismatch causes denial [OK]

Quick Trick: Password check is case sensitive [OK]

Common Mistakes:

Ignoring case sensitivity in password comparison
Assuming 'secure123' matches 'Secure123'
Expecting syntax errors from correct code

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More EV Technology Quizzes

Consider this code snippet for an EV's security system:

Step 1: Understand the password check logic

Step 2: Check the input password 'secure123'

Final Answer:

Quick Check:

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