[Solved] A tester wrote this code to check boundary values:def test_boundary(x): if x > 0 and x What is the problem with this test regarding boundary coverage? | Testing Fundamentals

Testing Fundamentals - Functional Testing Techniques

A tester wrote this code to check boundary values:

def test_boundary(x):
    if x > 0 and x < 10:
        return 'Inside'
    else:
        return 'Outside'

print(test_boundary(0))
print(test_boundary(10))

What is the problem with this test regarding boundary coverage?

AIt misses testing the exact boundary values 0 and 10 correctly.

BIt tests values outside the range only.

CIt uses incorrect syntax for the function.

DIt returns wrong strings for inputs.

Step-by-Step Solution

Solution:

Step 1: Understand boundary conditions in code
The code checks if x is strictly greater than 0 and less than 10, so 0 and 10 are excluded.
Step 2: Identify test coverage issue
Testing 0 and 10 returns 'Outside', missing the boundary values as 'Inside' cases.
Final Answer:
It misses testing the exact boundary values 0 and 10 correctly. -> Option A
Quick Check:
Boundary values excluded = coverage gap [OK]

Quick Trick: Check if boundaries are included or excluded in conditions [OK]

Common Mistakes:

MISTAKES

Assuming 0 and 10 are inside the range
Ignoring strict inequality signs
Thinking syntax error causes the problem

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More Testing Fundamentals Quizzes

A tester wrote this code to check boundary values:

Step 1: Understand boundary conditions in code

Step 2: Identify test coverage issue

Final Answer:

Quick Check:

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