[Solved] The following pseudo-code is intended to perform a smoke test but has an error:def smoke_test(build): if build['feature'] = 'ready': return 'Pass' else:... | Testing Fundamentals

Testing Fundamentals - Testing Types and Levels

The following pseudo-code is intended to perform a smoke test but has an error:

def smoke_test(build):
    if build['feature'] = 'ready':
        return 'Pass'
    else:
        return 'Fail'

What is the error and how to fix it?

ARemove the else block entirely

BChange 'return' to 'print' statements

CUse '==' for comparison instead of '=' assignment

DAdd a semicolon at the end of the if line

Step-by-Step Solution

Solution:

Step 1: Identify syntax error in condition
The code uses '=' which is assignment, not comparison, causing a syntax error.
Step 2: Correct the operator
Replace '=' with '==' to compare values properly.
Final Answer:
Use '==' for comparison instead of '=' assignment -> Option C
Quick Check:
Comparison needs '==' not '=' [OK]

Quick Trick: Use '==' to compare, '=' assigns [OK]

Common Mistakes:

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