[Solved] Why is Swift considered strongly typed even though it supports type inference? — Ans: Because it always knows the exact type at compile time | Swift

Swift - Data Types

Why is Swift considered strongly typed even though it supports type inference?

ABecause it never requires specifying types explicitly

BBecause it ignores types during compilation

CBecause it always knows the exact type at compile time

DBecause it allows variables to change types dynamically

Step-by-Step Solution

Solution:

Step 1: Understand type inference
Swift can guess the type from the assigned value without explicit annotation.
Step 2: Recognize strong typing with inference
Even with inference, Swift knows the exact type at compile time and enforces it.
Final Answer:
Because it always knows the exact type at compile time -> Option C
Quick Check:
Type inference still enforces strong typing [OK]

Quick Trick: Inference guesses type but keeps strong typing [OK]

Common Mistakes:

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