[Solved] What will be the output of the following Swift code?var name: String? = "Alice" if let unwrappedName = name { print("Hello, \(unwrappedName)!") } else { print("No name provided.") } | Swift

Swift - Optionals

What will be the output of the following Swift code?

var name: String? = "Alice"
if let unwrappedName = name {
    print("Hello, \(unwrappedName)!")
} else {
    print("No name provided.")
}

ANo name provided.

BHello, Alice!

COptional("Alice")

DError: Cannot unwrap optional

Step-by-Step Solution

Solution:

Step 1: Understand optional binding with if let
The code uses 'if let' to safely unwrap the optional 'name'. Since 'name' contains "Alice", unwrapping succeeds.
Step 2: Determine which print statement runs
Because unwrapping succeeds, the first print statement runs, printing "Hello, Alice!".
Final Answer:
Hello, Alice! -> Option B
Quick Check:
Optional binding unwraps value = prints greeting [OK]

Quick Trick: if let unwraps optionals safely [OK]

Common Mistakes:

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