[Solved] Identify the error in this Swift code: var name = "Alice" name = 42 print(name) — Ans: Type mismatch error when assigning 42 to name | Swift

Swift - Variables and Constants

Identify the error in this Swift code:

var name = "Alice"
name = 42
print(name)

ASyntax error on variable declaration

BNo error, prints 42

CType mismatch error when assigning 42 to name

DRuntime error when printing

Step-by-Step Solution

Solution:

Step 1: Check variable type inference
Variable name is inferred as String because of initial value "Alice".
Step 2: Assign incompatible type
Assigning an integer 42 to a String variable causes a type mismatch error.
Final Answer:
Type mismatch error when assigning 42 to name -> Option C
Quick Check:
Swift variables keep type, cannot assign different type [OK]

Quick Trick: Variable type fixed by first value, cannot assign different type [OK]

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