[Solved] Identify the error in the following Swift code snippet:typealias Name = String func greet(name: Name) { print("Hello, \(Name)!") } greet(name: "Alice") | Swift

Swift - Variables and Constants

Identify the error in the following Swift code snippet:

typealias Name = String

func greet(name: Name) {
    print("Hello, \(Name)!")
}
greet(name: "Alice")

AUsing <code>Name</code> inside the print instead of the parameter <code>name</code>

BIncorrect typealias syntax

CMissing return type in function

DCannot use typealias as function parameter type

Step-by-Step Solution

Solution:

Step 1: Check the function parameter and usage
The function parameter is named name, but inside print, Name (the type alias) is used instead.
Step 2: Understand the difference between parameter and typealias
Name is a type alias, not a variable holding the value. The print should use name to print the argument.
Final Answer:
Using Name inside the print instead of the parameter name -> Option A
Quick Check:
Use parameter name, not typealias name [OK]

Quick Trick: Use variable names, not typealias names inside functions [OK]

Common Mistakes:

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