[Solved] Identify the error in this Swift code:var value: Int? value = 5 print(value!) — Ans: Force unwrapping without checking nil can cause runtime error | Swift

Swift - Optionals

Identify the error in this Swift code:

var value: Int?
value = 5
print(value!)

AOptional variable cannot be assigned a value

BForce unwrapping without checking nil can cause runtime error

CMissing declaration of value as non-optional

DSyntax error in variable declaration

Step-by-Step Solution

Solution:

Step 1: Analyze force unwrapping usage
Using value! force unwraps the optional without checking if it is nil.
Step 2: Check if value is nil before unwrapping
Since value is assigned 5, force unwrap works here, but if it were nil, it would cause a runtime error.
Final Answer:
Force unwrapping without checking nil can cause runtime error -> Option B
Quick Check:
Force unwrap risky without nil check [OK]

Quick Trick: Always check nil before force unwrapping optionals [OK]

Common Mistakes:

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