[Solved] Why does Swift not allow implicit fallthrough in switch statements like C or Java? — Ans: To prevent accidental execution of multiple cases and improve safety | Swift

Swift - Control Flow

Why does Swift not allow implicit fallthrough in switch statements like C or Java?

ATo force programmers to write longer code

BTo prevent accidental execution of multiple cases and improve safety

CBecause Swift does not support switch statements

DBecause fallthrough is deprecated in Swift

Step-by-Step Solution

Solution:

Step 1: Understand Swift design goals
Swift aims to reduce bugs by preventing accidental fallthrough in switch.
Step 2: Analyze options
To prevent accidental execution of multiple cases and improve safety correctly explains the safety motivation behind no implicit fallthrough.
Final Answer:
To prevent accidental execution of multiple cases and improve safety -> Option B
Quick Check:
No implicit fallthrough improves code safety and clarity [OK]

Quick Trick: No implicit fallthrough avoids accidental multi-case execution [OK]

Common Mistakes:

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Why does Swift not allow implicit fallthrough in switch statements like C or Java?