Swift - Loops
You want to print all pairs (i, j) for i and j from 1 to 3, but skip printing pairs where i + j is 4 or more, and stop all loops immediately if i equals 3. Which labeled statement structure correctly implements this in Swift?
Which labeled statement structure correctly implements this in Swift?
hard📝 Application Q8 of 15
Step-by-Step Solution
Solution:
Step 1: Understand conditions order
We must break outer loop immediately if i == 3 before printing.Step 2: Check continue condition
Skip printing pairs where i + j >= 4 using continue inside inner loop.Step 3: Verify labeled break usage
outer: for i in 1...3 { for j in 1...3 { if i == 3 { break outer } if i + j >= 4 { continue } print("\(i),\(j)") } } breaks outer loop when i == 3 before continue or print.Final Answer:
Option B correctly implements the logic -> Option BQuick Check:
Break outer first, then continue inner [OK]
Quick Trick: Check break conditions before continue and print [OK]
Common Mistakes:
- Placing break after continue or print
- Using continue with wrong label
- Misordering conditions causing wrong output
Master "Loops" in Swift
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