[Solved] Consider this Swift function:func checkInput(_ input: String?) { guard let value = input else { print("No input provided") return } print("Input:... | Swift

Swift - Optionals

Consider this Swift function:

func checkInput(_ input: String?) {
    guard let value = input else {
        print("No input provided")
        return
    }
    print("Input: \(value)")
}

What will happen if checkInput(nil) is called?

AIt prints "No input provided" and exits the function early.

BIt prints "Input: nil" and continues execution.

CIt causes a runtime error due to force unwrapping.

DIt skips the guard statement and prints nothing.

Step-by-Step Solution

Solution:

Step 1: Analyze guard let behavior
If input is nil, the else block executes.
Step 2: What does the else block do?
It prints "No input provided" and returns, exiting the function early.
Final Answer:
It prints "No input provided" and exits the function early. -> Option A
Quick Check:
Guard else block runs on nil input [OK]

Quick Trick: Guard else runs and returns on nil [OK]

Common Mistakes:

Assuming it prints "Input: nil"
Expecting a runtime error from guard let
Thinking guard lets code continue after nil

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More Swift Quizzes

Consider this Swift function:

Step 1: Analyze guard let behavior

Step 2: What does the else block do?

Final Answer:

Quick Check:

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