[Solved] What will be printed when this Swift code runs?func checkAge(_ age: Int?) { guard let age = age, age >= 18 else { print("Access denied") return } print("Access granted") } checkAge(nil) checkAge(20) | Swift

Swift - Optionals

What will be printed when this Swift code runs?

func checkAge(_ age: Int?) {
    guard let age = age, age >= 18 else {
        print("Access denied")
        return
    }
    print("Access granted")
}
checkAge(nil)
checkAge(20)

AAccess granted\nAccess granted

BNo output

CAccess denied\nAccess denied

DAccess denied\nAccess granted

Step-by-Step Solution

Solution:

Step 1: Analyze first call checkAge(nil)
age is nil, guard let fails, else block runs printing "Access denied" and returns.
Step 2: Analyze second call checkAge(20)
age unwraps to 20, condition age >= 18 is true, so prints "Access granted".
Final Answer:
Access denied\nAccess granted -> Option D
Quick Check:
guard let with condition = correct output [OK]

Quick Trick: guard let with multiple conditions exits early if any fail [OK]

Common Mistakes:

Assuming nil passes guard
Ignoring condition after unwrapping
Expecting no output on nil

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What will be printed when this Swift code runs?

Step 1: Analyze first call checkAge(nil)

Step 2: Analyze second call checkAge(20)

Final Answer:

Quick Check:

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