[Solved] What happens if the condition in a guard let statement fails in Swift? — Ans: The code inside the else block runs and the function exits early | Swift

Swift - Optionals

What happens if the condition in a guard let statement fails in Swift?

AThe program crashes immediately

BThe code inside the else block runs and the function exits early

CThe optional value is force unwrapped

DThe code after the guard statement is skipped but function continues

Step-by-Step Solution

Solution:

Step 1: Understand guard let behavior
The guard statement checks if the optional can be unwrapped. If it cannot, the else block runs.
Step 2: Early exit on failure
Inside the else block, you must exit the current scope (return, break, continue, or throw). This stops further execution.
Final Answer:
The code inside the else block runs and the function exits early -> Option B
Quick Check:
guard let failure = early exit [OK]

Quick Trick: guard let forces early exit if unwrapping fails [OK]

Common Mistakes:

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