You have an array of integers and want to create a new array with only the even numbers using a for-in loop. Which code correctly does this?

hard📝 Application Q8 of 15

Swift - Loops

Alet evens = [] for num in numbers { if num % 2 == 0 { evens.append(num) } }

Bvar evens = [Int]() for num in numbers { if num % 2 == 0 { evens.append(num) } }

Cvar evens = [Int] for num in numbers { if num % 2 == 0 { evens.append(num) } }

Dvar evens = Array for num in numbers { if num % 2 == 0 { evens.append(num) } }

Step-by-Step Solution

Solution:

Step 1: Initialize an empty array correctly
var evens = [Int]() for num in numbers { if num % 2 == 0 { evens.append(num) } } uses 'var evens = [Int]()' which correctly creates an empty integer array.
Step 2: Use for-in loop with condition and append
The loop checks if a number is even and appends it to evens array.
Final Answer:
var evens = [Int]()\nfor num in numbers {\n if num % 2 == 0 {\n evens.append(num)\n }\n} -> Option B
Quick Check:
Empty array init + append even numbers [OK]

Quick Trick: Initialize empty array with [Type]() before appending [OK]

Common Mistakes:

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