You want to find customers who placed more than 3 orders and spent over $500 total. Which query pattern correctly achieves this?

hard📝 Application Q15 of 15

SQL - Advanced Query Patterns

SELECT customer_id, COUNT(*), SUM(amount) FROM orders GROUP BY customer_id HAVING COUNT(*) > 3 AND SUM(amount) > 500;

AUse WHERE to filter counts and sums after grouping.

BUse GROUP BY only without HAVING or WHERE.

CUse HAVING to filter groups based on aggregated values.

DUse ORDER BY to filter groups with conditions.

Step-by-Step Solution

Solution:

Step 1: Understand filtering after aggregation
WHERE filters rows before grouping; HAVING filters groups after aggregation.
Step 2: Identify correct clause for aggregated conditions
Conditions on COUNT and SUM require HAVING, not WHERE.
Final Answer:
Use HAVING to filter groups based on aggregated values. -> Option C
Quick Check:
HAVING filters aggregated group results [OK]

Quick Trick: Use HAVING for conditions on grouped data [OK]

Common Mistakes:

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