[Solved] You want to assign a sequential rank to salespeople within each region, but if two salespeople have the same sales amount, they should get... Which window function with PARTITION BY should you use? | SQL

SQL - Window Functions Fundamentals

You want to assign a sequential rank to salespeople within each region, but if two salespeople have the same sales amount, they should get different ranks (no ties). Which window function with PARTITION BY should you use?

ADENSE_RANK() OVER (PARTITION BY Region ORDER BY SalesAmount DESC)

BROW_NUMBER() OVER (PARTITION BY Region ORDER BY SalesAmount DESC)

CRANK() OVER (PARTITION BY Region ORDER BY SalesAmount DESC)

DSUM(SalesAmount) OVER (PARTITION BY Region)

Step-by-Step Solution

Solution:

Step 1: Understand difference between ROW_NUMBER, RANK, and DENSE_RANK
ROW_NUMBER assigns unique sequential numbers without ties; RANK and DENSE_RANK assign same rank to ties.
Step 2: Choose function that assigns unique ranks per region
ROW_NUMBER() OVER (PARTITION BY Region ORDER BY SalesAmount DESC) fits requirement.
Final Answer:
ROW_NUMBER() OVER (PARTITION BY Region ORDER BY SalesAmount DESC) -> Option B
Quick Check:
ROW_NUMBER() = unique ranks, no ties [OK]

Quick Trick: Use ROW_NUMBER() for unique ranks, RANK() allows ties [OK]

Common Mistakes:

Using RANK() or DENSE_RANK() when unique ranks needed
Confusing SUM() with ranking functions
Omitting PARTITION BY for per-group ranking

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Which window function with PARTITION BY should you use?

Step 1: Understand difference between ROW_NUMBER, RANK, and DENSE_RANK

Step 2: Choose function that assigns unique ranks per region

Final Answer:

Quick Check:

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