How can you modify this query to find duplicate usernames but also show how many times each username appears? SELECT username FROM users GROUP BY username HAVING COUNT(*) > 1;

hard📝 Application Q9 of 15

SQL - Advanced Query Patterns

AAdd COUNT(*) in SELECT: SELECT username, COUNT(*) FROM users GROUP BY username HAVING COUNT(*) > 1;

BAdd COUNT(*) in WHERE clause

CAdd COUNT(*) in ORDER BY clause only

DUse DISTINCT instead of GROUP BY

Step-by-Step Solution

Solution:

Step 1: Understand the original query
It finds usernames appearing more than once but does not show counts.
Step 2: Add COUNT(*) to SELECT to display counts
Including COUNT(*) in SELECT with GROUP BY shows how many times each username appears.
Final Answer:
SELECT username, COUNT(*) FROM users GROUP BY username HAVING COUNT(*) > 1; -> Option A
Quick Check:
Include COUNT(*) in SELECT to show duplicates count [OK]

Quick Trick: Add COUNT(*) in SELECT to display duplicate counts [OK]

Common Mistakes:

Using WHERE with COUNT
Adding COUNT(*) only in ORDER BY
Replacing GROUP BY with DISTINCT

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How can you modify this query to find duplicate usernames but also show how many times each username appears? SELECT username FROM users GROUP BY username HAVING COUNT(*) > 1;

Step 1: Understand the original query

Step 2: Add COUNT(*) to SELECT to display counts

Final Answer:

Quick Check:

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