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Why might a Spring Boot application fail to deserialize JSON into a Java object?

medium📝 Debug Q7 of 15
Spring Boot - Messaging
Why might a Spring Boot application fail to deserialize JSON into a Java object?
AThe JSON contains extra fields not in the Java class
BMissing a no-argument constructor in the Java class
CThe Java class implements Serializable
DThe Java class uses public getters and setters
Step-by-Step Solution
Solution:

  1. Step 1: Understand deserialization requirements

    Jackson requires a no-argument constructor to create an instance before setting fields.

  2. Step 2: Identify cause of failure

    If missing, deserialization fails because object cannot be instantiated.

  3. Final Answer:

    Missing a no-argument constructor in the Java class -> Option B

  4. Quick Check:

    No-arg constructor needed for deserialization [OK]
Quick Trick: Always provide a no-arg constructor for deserialization [OK]
Common Mistakes:
  • Assuming Serializable interface affects deserialization
  • Thinking extra JSON fields cause failure by default
  • Believing getters/setters alone fix deserialization

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