[Solved] Given this Spring Boot aspect code snippet:@Aspect public class LoggingAspect { @Before("execution(* com.example.... } }What will happen when a method in com.example.service package is called? | Spring Boot

Spring Boot - Aspect-Oriented Programming

Given this Spring Boot aspect code snippet:

@Aspect
public class LoggingAspect {
  @Before("execution(* com.example.service.*.*(..))")
  public void logBefore() {
    System.out.println("Method called");
  }
}

What will happen when a method in com.example.service package is called?

AThe message "Method called" will print after the method executes

BThe message "Method called" will print before the method executes

CNo message will print because the pointcut is incorrect

DThe method call will be blocked and not executed

Step-by-Step Solution

Solution:

Step 1: Understand the @Before advice
The @Before annotation means the method logBefore() runs before the matched method executes.
Step 2: Analyze the pointcut expression
The pointcut execution(* com.example.service.*.*(..)) matches any method in any class inside com.example.service package.
Final Answer:
The message "Method called" will print before the method executes -> Option B
Quick Check:
@Before advice prints message before method [OK]

Quick Trick: @Before runs code before matched methods [OK]

Common Mistakes:

Confusing @Before with @After advice
Thinking pointcut matches other packages
Assuming method is blocked

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More Spring Boot Quizzes

Given this Spring Boot aspect code snippet:

Step 1: Understand the @Before advice

Step 2: Analyze the pointcut expression

Final Answer:

Quick Check:

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