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Which of the following is the correct way to serialize a Java object to a JSON string using Jackson's ObjectMapper?

easy📝 Syntax Q12 of 15
Spring Boot - Request and Response Handling
Which of the following is the correct way to serialize a Java object to a JSON string using Jackson's ObjectMapper?
AobjectMapper.readValue(object, String.class);
BobjectMapper.writeValueAsString(object);
CobjectMapper.toJson(object);
DobjectMapper.serialize(object);
Step-by-Step Solution
Solution:
  1. Step 1: Identify the serialization method in ObjectMapper

    The method to convert an object to JSON string is writeValueAsString.
  2. Step 2: Check other options for correctness

    readValue is for deserialization, toJson and serialize are not valid ObjectMapper methods.
  3. Final Answer:

    objectMapper.writeValueAsString(object); -> Option B
  4. Quick Check:

    Serialize with writeValueAsString() [OK]
Quick Trick: Use writeValueAsString() to convert object to JSON string [OK]
Common Mistakes:
  • Using readValue() instead of writeValueAsString()
  • Assuming toJson() or serialize() exist in ObjectMapper
  • Mixing serialization and deserialization methods

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