Spring Boot - Request and Response HandlingWhich of the following is the correct way to serialize a Java object to a JSON string using Jackson's ObjectMapper?AobjectMapper.readValue(object, String.class);BobjectMapper.writeValueAsString(object);CobjectMapper.toJson(object);DobjectMapper.serialize(object);Check Answer
Step-by-Step SolutionSolution:Step 1: Identify the serialization method in ObjectMapperThe method to convert an object to JSON string is writeValueAsString.Step 2: Check other options for correctnessreadValue is for deserialization, toJson and serialize are not valid ObjectMapper methods.Final Answer:objectMapper.writeValueAsString(object); -> Option BQuick Check:Serialize with writeValueAsString() [OK]Quick Trick: Use writeValueAsString() to convert object to JSON string [OK]Common Mistakes:Using readValue() instead of writeValueAsString()Assuming toJson() or serialize() exist in ObjectMapperMixing serialization and deserialization methods
Master "Request and Response Handling" in Spring Boot9 interactive learning modes - each teaches the same concept differentlyLearnWhyDeepVisualTryChallengeProjectRecallPerf
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